You burn a 1.5 g jellybean to warm 150 g of water. the temperature of the water increases by 15 °c. water has a specific heat of 4.184 j/g • °c. how many joules does the jellybean have? a) 94.14 j b)941.4 j c)9414 j d)14124 j

9414.0 J.

Explanation:

Q = m.c.ΔT.

where, Q is the amount of heat absorbed by water,

m is the mass of water (m = 150.0 g),

c is the specific heat of water (c = 4.184 J/g °C),

ΔT is the temperature difference (final T - initial T) (ΔT = 15.0 °C).

∴ Q = m.c.ΔT = (150.0 g)(4.184 J/g °C)(15.0 °C) = 9414.0 J.

the answer is d : ) have a good da