If a gas has a volume of 1000 ml at a temperature of 23°c and a pressure of 100 mmhg, what is it’s volume under standard conditions of temperature and pressure?

119.7 mL.

Explanation:

PV = nRT.

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

P₁V₁/T₁ = P₂V₂/T₂.

∴ V₂ = (P₁V₁T₂)/(T₁P₂) = (100.0 mmHg)(1000.0 mL)(273.0 K)/(296 K)(760.0 mmHg) =  121.4 mL.

the answer for sodium is 0.186

the answer for rubidium is 0.251