How much energy is required to heat a chunk of ice that weighs 510g from -256°c to 195°c

The ice undergoes several transformations. First it absorbs energy and its temperature to raise the temperature to 0°C the melting point of water. Then the ice absorbs latent heat of fusion to melt, then absorbs heat to raise the temperature to 100°C the boiling point of water. then the steam is heated to 195°C

Therefore the following expression is used to calculate the heat required to make these changes

MC∅(ice)+MLf(ice)+MC∅(water)+MLv(water)+MC∅(water vapor)

0.51kg×2.108kJ/KgK×(0--256)K+0.51×333.55kJ/Kg+0.51kg×4.2 kJ/KgK×(100-0)+0.51kg×2260kJ/kg+ 0.51kg×1.996kJ/kgK× (195-100)K

= 1908.84kJ

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.