(30 points) how many kilojoules of heat are absorbed when 1.00 l of water is heated from 19*c to 82*c?
show work : )

264.6kJ

Explanation:

Assuming the water is pure, then it has a density of 1000kg/m³= 1g/cm³

1 liter will be equivalent to 1000cm³.

Mass will be: density×volume

1g/cm³×1000cm³=1000g

in kg it will be 1kg

The specific heat capacity of pure water is 4.2kJ/kgK

We use the formula MC∅ where ∅ is the temperature change.

Therefore the heat absorbed will be:

1kg×4.2kJ/kgK× (82-19)K= 264.6kJ

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