How many milliliters of 0.258m naoh are required to completely neutralize 2.00 g of acetic acid hc2h3o2?

0.129 L = 129.0 mL.

Explanation:

NaOH + CH₃COOH → CH₃COONa + H₂O.  

no. of moles of CH₃COOH = mass/molar mass = (2.0 g)/(60 g/mol) = 0.033 mole.  

no. of moles = (0.258 mol/L)(V)

∴ (0.258 mol/L)(V) = 0.033 mole

∴ The volume of NaOH =  (0.033 mole)/(0.258 mol/L) = 0.129 L = 129.0 mL.

a. hope i'm right

explanation:

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.