What is the molarity of a solution that contains 17 g of nh3 in 0.50 l of solution?

Explanation:

1) Data:

a) M = ?

b) mass of solue = 17 g

c) solute: NH₃

d) V = 0.5o liter

2) Formulae:

a) number of moles, n = mass in grams / molar mass

b) M = n / V (in liters)

3) Solution

a) Molar mass of NH₃ = 17.03 g/mol

b) n = mass in grams / molar mass = 17 g / 17.03 g/mol = 0.998 mol NH₃

c) M = n / V (in liters) = 0.998 mol / 0.50 liter = 1.996 M

d) Round to the appropiate number of significant figures, 2: 2.0 M.

2.0 M

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