0.60 moles of potassium nitrate is dissolved in 300 mililiters of solution

= 2 M or 2 mol/Liter

Explanation:

Molarity or concentration is calculated by the formula;

Molarity = Number of moles/ Volume in liters

In this case;

Moles = 0.6 moles

Volume in L = 0.3 L

Therefore;

Molarity = 0.6 mol/0.3 L

             = 2 M  or 2 moles/Liter

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm