For a gas to be soluble in water, the gas should contain (nonpolar, polar ) molecules. the water should be at a (high, low) temperature, and the gas should be at (high, low ) pressure above the surface of the water.

The gas should contain polar molecules. The water should be at a low temperature, and the gas should be at high pressure above the surface of the  water.

Explanation:

Water is a dipolar molecule due to presence of electronegative oxygen atom as well as angular structure of water molecule.

So water attracts polar molecules through dipole-dipole attraction force and hence polar molecules get dissolved into water.

Water should have low temperature during dissolution of gas into water. Because, at high temperature, intermolecular force between gas and water molecule tend to break apart.

At high pressure, gas molecules are forced to enter into bulk liquid. Thus dissolution of gas into liquid becomes favorable.

Explanation:

It is known that water is a polar molecule due to the difference in electronegativity of hydrogen and oxygen atom there is a positive partial charge on hydrogen and a negative partial charge on the oxygen atom.

So, being a polar molecule water readily dissolve substance which are also polar in nature.

Hence, for a gas to be soluble in water it is required that the gas should contain polar molecules.

Also, water should be at low temperature because otherwise gas will evaporate from the solution due more gain in kinetic energy.

As, Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, as follows.

where,         = Henry's constant =

                  = partial pressure a gas

Therefore, pressure of the gas should be high at the surface of water.

Thus, we can conclude that for a gas to be soluble in water, the gas should contain polar molecules. The water should be at a low temperature, and the gas should be at high pressure above the surface of the water.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

answer:

technetium is the most reactive. this is followed by silver. the least reactive out of these three elements is strontium.