What is the final temperature of a sample of nickel (cnickel =0.54j/g°c) if 328j of energy is added to a 16.7g sample at an initial temperature of 24.4°c?

60.77°C.

Explanation:

Q = m.c.ΔT.

where, Q is the amount of heat absorbed by Ni (Q = 328 J),

m is the mass of Ni (m = 16.7 g),

c is the specific heat capacity of Ni (c = 0.54 J/g °C),

ΔT is the temperature difference (final T - initial T) (ΔT = final T - 24.4°C).

∵ Q = m.c.ΔT.

∴ (328 J) = (16.7 g)(0.54 J/g °C)(final T - 24.4°C)

(final T - 24.4°C) = (328 J)/(16.7 g)(0.54 J/g °C) = 36.37°C.

∴ final T = 36.37°C + 24.4°C = 60.77°C.

the correct answer is:

a. formation of precipitation