A225 g sample of an unknown solid is heated 67c and placed into a calorimeter containing 25.6 g of water at 15.6°c. if the final temperature of the solid sample and the water is 53°c, what is the specific heat of the solid?

= 1.271 J/g°C

Explanation:

Heat released by the metal sample will be equivalent to the heat absorbed by  water.

But heat = mass × specific heat capacity × temperature change

Thus;

Heat released by the solid;

= 225 g × c ×(67 -53) , where c is the specific heat capacity of the metal

= 3150 c joules

Heat absorbed by water;

= 25.6 g × 4.18 J/g°C × (53-15.6)

= 4002.0992  joules

Therefore;

3150 c joules = 4002.0992 joules

c =4002.0992/3150

  = 1.271 J/g°C

the answer is symmetrical : )