Helium occupies a volume of 3.8 liters at -45 degrees c. what volume will it occupy at 75 degrees c?

5.8 L.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

V₁T₂ = V₂T₁

V₁ = 3.8 L, T₁ = - 45.0°C + 273 = 228.0 K.

V₂ = ??? L, T₂ = 75.0°C + 273 = 348.0 K.

∴ V₂ = V₁T₂/T₁ = (3.8 L)(348.0 K)/(228.0 K) = 5.8 L.

idk

explanation:

dasdad

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.