Balance this reaction al4c + h2o = al(oh)+ ch4

Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄

Explanation:

The correct formulas are

Al₄C₃ + H₂O ⟶ Al(OH)₃ + CH₄

Often, the best way to start is to balance all atoms other than O and H, then balance O, then balance H.

1. Put a 1 in front of the most complicated-looking formula (Al₄C₃):

1Al₄C₃ + H₂O ⟶ Al(OH)₃ + CH₄

2. Balance Al:

We have fixed 4 Al on the left. We need 4 Al on the right. Put a 4 in front of Al(OH)₃.

1Al₄C₃ + H₂O ⟶ 4Al(OH)₃ + CH₄

3. Balance C:

We have fixed 3 C on the left. We need 3 C on the right. Put a 3 in front of CH₄.

1Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄

4. Balance O:

We have fixed 12 O on the right. We need 12 O on the left. Put a 12 in front of H₂O.

1Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄

Every formula now has a fixed coefficient. The equation should be balanced.

5. Check that atoms balance:

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The balanced equation is

Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying