Nitrogen in a 29 l container at a pressure of 398 mm hg and 293 k is transferred to a container with a pressure of 307 mm hg. what is the new temperature if the volume changes to 156 l?

70.61°c=T₂

Explanation:

This question is on Combined Gas Laws

The volume of a gas is directly proportional to the absolute temperature and inversely proportional to the pressure.

P₁V₁T₁=P₂V₂T₂

where

P₁=Initial pressure, P₂=final pressure

V₁=Initial volume,V₂=final volume

T₁=Initial temperature in Kevin, T₂=final temperature in Kelvin

Given

P₁=398mm Hg,  V₁=29 L  and T₁=293 K

P₂=307 mm Hg, V₂=156 L  and T₂=?

Solution

P₁V₁T₁=P₂V₂T₂

Substitute values

398×29×293=307×156×T₂

3381806=47892T₂

3381806/47892=T₂

70.61°c=T₂

70.61+273=343.61 K

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

mark brainliest and have a great day!

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2