If a sample of a gas has an initial volume of 15 l and a pressure of 125 kpa what will the pressure of the gas be (in atm) if the volume is increased to 29 l?

apply Boyle's law

Boyle's Law, an ideal gas law which states that the volume of an ideal gas is inversely proportional to its absolute pressure at a constant temperature

V = 1/P

PV = 1

PV= constant

let 15L = V1 and 125kPa = P1

9L =V2 and P2 = ?

Now from Boyle's law

P1V1 = P2V2

Substitute the values

15L * 125kPa = 29 * P2

P2 = 64.65kPa

convert Pascal's into atm

1 pascal =

9.869 × 10-6 atmosphere

P2 = 64.65 *10^3 *9.869 × 10-6 (kPa is kilo Pascal's)

- lead + phosphoric acid = hydrogen + lead(ii) phosphate