Allicin (c6h10os2) contains 59.9 g of carbon, 21.7 g of hydrogen, 24.4 g of oxygen, and sulfur. what is the mass percent of sulfur in a 162 g sample of the compound?
a) 13.40%
b) 15.06%
c) 21.04%
d) 34.57%
e) 36.98%

Answer : The correct option is, (d) 34.57 %

Explanation: Given,

Mass of C = 59.9 g

Mass of H = 21.7 g

Mass of O and S = 24.4 g

Mass of sample = 162 g

First we have to calculate the mass of sulfur.

Total mass of allicin = Mass of C + Mass of H + Mass of O and S

Total mass of allicin = 59.9 + 21.7 + 24.4

Total mass of allicin = 106 g

Mass of sulfur = Mass of sample - Total mass of allicin

Mass of sulfur = 162 - 106

Mass of sulfur = 56 g

Now we have to calculate the mass percent of sulfur.

Formula used :

Now put all the given values in this formula, we get:

Therefore, the mass percent of sulfur is 34.57 %

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.