You need to know the volume of water in a small swimming pool, but, owing to the pool's irregular shape, it is not a simple matter to determine its dimensions and calculate the volume. to solve the problem, you stir in a solution of a dye (1.00 g of methylene blue, c16h18cln3s, in 50.0 ml of water). after the dye has mixed with the water in the pool, you take a sample of the water. using a spectrophotometer, you determine that the concentration of the dye in the pool is 3.74 × 10-8 m. what is the volume of water in the pool in liters? the molar mass of methylene blue is 319.854 g/mol.

83,700  liter (rounded to 3 significant figures)

Explanation:

1) Data:

a) Solution of a dye:

m₁ = 1.00 g of methylene blue, C₁₆H₁₈ClN₃SV₁ = 50.0 mL MM₁ = 319.854 g/mol

b) Water of the pool, after mixing the dye:

M₂ = 3.74 × 10⁻⁸ M. V₂ = ?

2) Formulae:

a) Molarity: M = n / V in liter

b) Molar mass: MM = mass in grams / number of moles

3) Solution:

a) Number of moles of methylene blue in the prepared solution:

n₁ = mass in grams / molar mass = = 1.00 g / 319.854 g/mol = 0.00313 mol

b) Number of moles of methylen blue in the pool = number of moles of methylen blue in the prepared solution

n₂ = n₁ = 0.00313 mol

c) Volume of the pool:

M₂ = n₂ / V₂ ⇒ V₂ = n₂ / M₂ = 0.00313 mol /( 3.74 × 10⁻⁸ M) = 83,700  liter

And that is the answer, which has to be rounded to 3 significant figures, since the data are expressed with 3 significant figures.

Note: For all the effects, the 50.0 mL of the dye solution are neglictible in front of the volume of the pool.

False because saturated fatty acids contain only single bond

If this is a true or galse then its true but if not then what is the question?