Under certain circumstances, carbon dioxide, co2(g), can be made to react with hydrogen gas, h2(g), to produce methane, ch4(g), and water vapor, h2o(g): co2(g)+4h2(g)→ch4(g)+2h2o(g)part a how many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas? express your answer with the appropriate units. for example, write the unit moles as mol. part b how many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 42.1 moles of water vapor? express your answer with the appropriate units. for example, write the unit moles as mol.

These are two questions and two answers.

Answers:

Explanation:

1) Balanced chemical equation (given):

2) Part A: How many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas?

a) Mole ratios:

b) Proportion:

         ⇒ x = 59.6 mol CH₄ ← answer

3) Part B How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 42.1 moles of water vapor?

a) Mole ratios:

b) Proportion:

         ⇒ x = 42.1 × 4 / 2 moles CH₄ = 84.2 mol H₂ (g) ← answer

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2