pcl3 (g) + cl2 (g) ↔ pcl5 (g) ∆h = –86 kj/mol
Chemistry, 25.10.2019 15:43 sistersquad
Consider the following reaction at equilibrium
pcl3 (g) + cl2 (g) ↔ pcl5 (g) ∆h = –86 kj/mol
what type of reaction is this?
me!
how will the equilibrium be affected by adding more of the product?
is the reaction endothermic or exothermic? how will the equilibrium be affected by adding heat?
how will the equilibrium be affected by increasing the pressure on the closed system?
explain the principle that you used in determining how the equilibrium is affected.
Answers: 3
Chemistry, 22.06.2019 04:00
Drag each label to the correct location on the chart. classify each reaction as endothermic or exothermic.
Answers: 1
Chemistry, 22.06.2019 13:50
Read the chemical equation. 2c2h2 + 5o2 → 4co2 + 2h2o which of the following statements would be correct if one mole of c2h2 was used in this reaction? one mole of oxygen was used in this reaction. five moles of oxygen were used in this reaction. four moles of carbon dioxide were produced from this reaction. two moles of carbon dioxide were produced from this reaction.
Answers: 3
Chemistry, 22.06.2019 21:30
Athe top of a hill, an athlete on a skateboard has x joules of mechanical energy. how much mechanical energy will she have at the bottom of the hill? ignore the effects of friction.
Answers: 1
Chemistry, 23.06.2019 03:00
You have a sample of a metal, the sample is exactly 6.02 x 1023atom, if the sample has a mass 55.85 what metal is your sample made of?
Answers: 2
Consider the following reaction at equilibrium
pcl3 (g) + cl2 (g) ↔ pcl5 (g) ∆h = –86 kj/mol
pcl3 (g) + cl2 (g) ↔ pcl5 (g) ∆h = –86 kj/mol
Mathematics, 09.07.2019 06:00
History, 09.07.2019 06:00
Mathematics, 09.07.2019 06:00
Mathematics, 09.07.2019 06:00
History, 09.07.2019 06:00
Mathematics, 09.07.2019 06:00
Mathematics, 09.07.2019 06:00
Spanish, 09.07.2019 06:00
Mathematics, 09.07.2019 06:00