A4,000 ml solution of agno3 contains 17.00 g of solute in water. calculate the molarity (molar concentration) of the solution.
3 x 10 -5m
3 x 10 -2m
4 x 10 -1m
1 x 10 -4m

2.5 x 10⁻² ≅ 3.0 x 10⁻² M.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (mass/molar mass)of AgNO₃/(V of the solution (L)).

∴ M of AgNO₃ = (17.0 g / 169.87 g/mol)/(4.0 L) = 2.5 x 10⁻² ≅ 3.0 x 10⁻² M.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

where,

n= moles of solute

= volume of solution in ml

moles of solute =

Now put all the given values in the formula of molarity, we get

Thus molarity of the solution will be

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation: