Which equation shows how to calculate how many grams (g) of mg(oh)2 would be produced from 4mol koh? the balanced reaction is:

mgcl2(small 2) + 2koh > mg(oh)2(small2) + 2kcl

4 mol of KOH would produce 116.6 g of Mg(OH)₂

Explanation:

According to the following balanced equation:

One can note that 2 mol of KOH react with MgCl₂ to produce 1 mol of Mg(OH)₂.

using cross multiplication  

2 mol of KOH → 1 mol of Mg(OH)₂.

4 mol of KOH → ?? mol of Mg(OH)₂.

no of moles of  Mg(OH)₂ = (1 mol* 4 mol) / 2 mol =2 mol

Now we can convert moles of  Mg(OH)₂ to grams using the formula

mass of Mg(OH)₂= (no. of moles * molar mass) = (2 mol * 58.3g/mol) = 116.6 g

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