Assign oxidation numbers for the following:
p2o5
(so4)2-
kclo3
nh4cl
(nh4)2s

show all the steps, .

1. P₂O₅      → oxidation number of phosphorous is +5 and Oxygen is -2.

2. (SO₄)²⁻ → oxidation number of sulfur is +6 and Oxygen is -2.

3. KClO₃   → oxidation number of Potassium is +1, Chlorine is +5, and Oxygen is -2.

4. NH₄Cl  → oxidation number of Nitrogen is -3, Hydrogen is +1, and Chlorine is -1

5. (NH₄)₂S  → oxidation number of Nitrogen is -3, Hydrogen is +1, and Sulfur is -2

Explanation:

General Rules for assigning oxidation numbers

The oxidation number of a free element is always 0.

The oxidation number of a mono-atomic ion equals the charge of the ion.

The alkali metals (group I) always have an oxidation number of +1.

The alkaline earth metals (group II) are always assigned an oxidation number of +2.

Oxygen almost always has an oxidation number of -2, except in peroxides (H₂O₂) where it is -1 and in compounds with fluorine (OF₂) where it is +2.

Hydrogen has an oxidation number of +1 when combined with non-metals, but it has an oxidation number of -1 when combined with metals.

The algebraic sum of the oxidation numbers of elements in a compound is zero.

The algebraic sum of the oxidation states in an ion is equal to the charge on the ion.

Using the above rules:

1. P₂O₅

∵ it is a neutral compound its total charge is 0.

Also, we know that oxygen has an oxidation number of -2.

Let oxidation number of P be x

∴ 2(x)+5(-2)=0   →   2x=+10   →   x=+5  

∴oxidation number of phosphorous is +5.

2. SO₄²⁻:

∵ it is a charged ion its total charge is -2.

Also, we know that oxygen has an oxidation number of -2.

Let oxidation number of S be x

∴ (x)+4(-2)= -2   →   x=+6  

∴oxidation number of sulfur is +6.

3. KClO₃:

∵ it is a neutral compound its total charge is 0.

Also, we know that oxygen has an oxidation number of -2 and the  oxidation number of K (group I) is +1

Let oxidation number of Cl be x

∴ (+1) + (x) + 3(-2) = 0   →   x=+5  

∴oxidation number of Chlorine is +5.

4. NH₄Cl:

∵ it is a neutral compound its total charge is 0.

Also, we know that chloride has an oxidation number of -1

Hydrogen has an oxidation number of +1 when combined with non-metals

 Let oxidation number of N be x

∴ (x) + 4(+1) + (-1) = 0   →   x=-3  

∴oxidation number of Nitrogen is -3.

5. (NH₄)₂S:

∵ it is a neutral compound its total charge is 0.

Also, we know that chloride has an oxidation number of -1

Ammonium ion (NH₄⁺) has an oxidation number of +1

 Let oxidation number of N be x

∴ 2(+1) + (x) = 0   →   x= -2  

∴oxidation number of sulfur is -2.

answer is: naturally occurring solid, inorganic compound or element is mineral.

minerals usually have crystalline form, that means than crystal constituents (atoms, molecules or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.

for example magnetite is a mineral of iron oxide (fe₂o₃).

calcite is a carbonate mineral and the most stable polymorph of calcium carbonate (caco₃).

dolomite is an   carbonate mineral composed of calcium magnesium carbonate (camg(co₃)₂).

can you attach the