3.00 moles of helium gas (he) are in a container with a volume is 2.00 liters and a temperature is at 298 k. what is the approximate pressure in kilopascals?

3718.628 kPa.

Explanation:

where, P is the pressure of the gas in atm (P = ??? atm).

V is the volume of the gas in L (V = 2.0 L).

n is the no. of moles of the gas in mol (n = 3.0 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 298.0 K).

∴ P = nRT/V = (3.0 mol)(0.0821 L.atm/mol.K)(298.0 K)/(2.0 L) = 36.7 atm.

∵ 1.0 atm = 101.325 kPa.

∴ P = (36.7 atm)(101.325 kPa/1.0 atm) = 3718.628 kPa.

answer; i believe that the correct answer is (a) potassium(k)