Given the following heats of combustion: c2h2(g) = -1300 kj/mole, h2(g) = -286 kj/mole, c2h6(g) = -1560 kj/mole, calculate the enthalpy change for the following reaction
c2h2(g) + 2h2(g) → c2h6(g)
a. -312 kj
b. -26 kj
c. +312 kj
d. -26 kj

Answer is A.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.