The reaction of sodium peroxide and water produces sodium hydroxide and oxygen gas. the following balanced chemical equation represents the reaction.

2 na^2o^2(s) + 2 h^2o(l) → 4 naoh(s) + o2(g)

how many moles of sodium hydroxide are produced when 17.2 mol sodium peroxide reacts with water?

34.4 mol.

Explanation:

2 Na₂O₂(s) + 2 H₂O(l) → 4 NaOH(s) + O₂(g),

It is clear that 2 moles of Na₂O₂ react with 2 moles of H₂O to produce 4 moles of NaOH and 1 mole of O₂.

Using cross multiplication:

2 moles of Na₂O₂ produce → 4 mole of NaOH.

17.2 moles of Na₂O₂ produce → ??? mole of NaOH.

∴ The no. of moles of NaOH produced = (4 mole)(17.2 mole)/(2 mole) =  34.4 mol.

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