Acontainer is filled with hydrogen gas. it has a volume of 4 liters and a pressure of 2 atm. if the pressure of the container is increased to 6 atm without removing any of the gas or changing the temperature, what will the new volume be

1.33 L.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

(P₁V₁) = (P₂V₂)

Knowing that:

V₁  =  4.0 L, P₁ = 2.0 atm,

V₂  =  ??? L, P₂ = 6.0 atm.

(P ₁V₁) = (P₂V₂)

∴ V₂ = P ₁V₁/P₂ = (2.0 atm)(4.0 L)/(6.0 atm) = 1.33 L.

2b2t

explanation:

2b2t

the answer would be a