A1.50-liter sample of dry air in a cylinder exerts a pressure of 3.0 atmospheres at a temperature of 25°c. without change in temperature, a piston is moved in the cylinder until the pressure in the cylinder is reduced to 1.0 atmosphere. what is the volume of the gas? (be sure to use the correct number of significant figures.) 0.22 l 0.50 l 2.0 l 4.5 l

4.5L

Explanation:

Given parameters:

Inital volume, V₁ of the dry air = 1.50L

Initial pressure P₁ = 3.0atm

Temperature = 25°C

Final pressure P₂ = 1.0atm

Final volume of gas,  V₂  = ?

To solve gas related problem, we apply Boyle's law based on the parameters given.

Boyle's law states that the volume of a fixed mass of gas is inversely proportional to the pressure provided that temperature is constant.

The law is simply expressed as:

                 P₁V₁ = P₂V₂

From the parameters given, the unknown V₂ which is the final volume.

Making  V₂ the subject of the equation gives:

                   V₂ =

                   V₂ = = 4.5L

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6