Chemistry, 04.02.2020 01:44 savannahwonder

13. a gas occupies 4.31 liters at a pressure of 0.755 atm. determine the volume if the
pressure
is increased to 1.25 atm.
14. 600.0 ml of a gas is at a pressure of 8.00 atm. what is the volume of the gas at 2.00
t
.

Answers: 3

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Answer from: xonyemaa12

13. The volume of the gas if the pressure is increased to 1.25 atm is 2.60 liters

14. The volume of the gas at 2.00 atm is 2400.0 mL

For the first question

To determine the volume of the gas,

We will use the equation from Boyle's law

Boyle's law states that "the volume of a fixed mass of gas is inversely proportional to its pressure, provided that the temperature remains constant".

From Boyle's law, we have that

P₁V₁ = P₂V₂

Where P₁ is the initial pressure

V₁ is the initial volume

P₂ is the final pressure

and V₂ is the final volume

From the question

P₁ = 0.755 atm

V₁ = 4.31 liters

P₂ = 1.25 atm

Put the above parameters into the equation to determine the final volume,

That is,

P₁V₁ = P₂V₂ becomes

0.755 × 4.31 = 1.25 × V₂

∴ V₂ = $\frac{0.755 \times 4.31}{1.25}$

V₂ = $\frac{3.25405}{1.25}$

V₂ = 2.60324

V₂≅ 2.60 liters

Hence, the volume of the gas if the pressure is increased to 1.25 atm is 2.60 liters

For the second question

We are to determine the volume of the gas at 2.00 atm

From the question

P₁ = 8.00 atm

V₁ = 600.0 mL

P₂ = 2.00 atm

Put the above parameters into the Boyle's law equation to determine the final volume,

That is,

P₁V₁ = P₂V₂ becomes

8 × 600 = 2.00 × V₂

∴ V₂ = $\frac{8.00 \times 600.0}{2.00}$

V₂ = $\frac{4800}{2.00}$

V₂ = 2400.0 mL

Hence, the volume of the gas at 2.00 atm is 2400.0 mL

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Answer from: cookiebrain72

13. 2.60 L.

14. 2.40 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the pressure is increased to 1.25 atm.

P₁ = 0.755 atm, V₁ = 4.31 L.

P₂= 1.25 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (0.755 atm)(4.31 L)/(1.25 atm) = 2.60 L.

14. 600.0 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at 2.00 at m.

P₁ = 8.0 atm, V₁ = 600.0 mL.

P₂= 2.0 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (8.0 atm)(600.0 mL)/(2.0 atm) = 2400/0 mL = 2.40 L.

Answer from: Quest

answer: lol

explanation:

lol

Answer from: Quest

The answer is probably c. xylem

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