Asample of nitrogen occupies 10.0 liters at 25°c and 98.7 kpa. what would be the volume at 20°c and 102.7 kpa?

   9.4 liter

Explanation:

1) Data:

 V₁ = 10.0 L  T₁ = 25°C = 25 + 273.15 K = 298.15 K   P₁ = 98.7 Kpa   T₂ = 20°C = 20 + 273.15 K = 293.15 K    P₂ = 102.7 KPa    V₂ = ?

2) Formula:

Used combined law of gases:

   PV / T = constant    P₁V₁ / T₁ = P₂V₂ / T₂

3) Solution:

Solve the equation for V₂:

   V₂ = P₁V₁ T₂ / (P₂ T₁)

Substitute and compuite:

V₂ = P₁V₁ T₂ / (P₂ T₁) V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K) V₂ =  9.4 liter ← answer

You can learn more about gas law problems reading this other answer on : link.