When 7.50 l of sulfur trioxide are produced by the reaction of sulfur dioxide in an excess of oxygen at standard temperature and pressure, how many liters of sulfur dioxide were used? 2so2 (g) + o2 (g) yields 2so3 (g)?

Explanation:

For this problem,  we must use Gay-Lussac's Law of  Combining Volumes:

The ratio in which gases react is the same as the ratio of their coefficients in the balanced equation.

The balanced equation is

Theor: 2 L                2 L  

         2SO₂ + O₂ ⟶2 SO₃

V/L:                           7.50

Gay-Lussac's Law tells us that 2 L of SO₂ form 2 L of SO₃.

The volume of SO₂ used was

the answer is   c.) 1575 j.

explanation:

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer