Chemistry, 28.06.2019 14:00 KJourdan19

Iodine, i2, has many uses, including the production of dyes, antiseptics, photographic film, pharmaceuticals, and medicinal soaps. it forms when chlorine, cl2, reacts with iodide ions in a sodium iodide solution. which of the following half-reactions for this oxidation‑reduction reaction describes the oxidation, and which one describes the reduction? cl2 + 2e‒ → 2cl‒ 2i‒ → i2 + 2e‒

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Answer from: itssamuelu

2I ⁻ → I₂ + 2e⁻ describes the oxidation.Cl₂ + 2e⁻ → 2Cl ⁻ describes the reduction.

Explanation:

Oxidation-reduction reaction is the simulaneous oxidation and reduction of the substances and is represented by two half-reactions.

The oxidation half-reaction is the loss of electrons, with the consequent increase in the oxidation state by the oxidized substance.

In this case, the process that shows the loss of electrons is:

2I⁻ → I₂ + 2e⁻

That reaction shows:

Two I⁻ ions lose two electrons (one each) to be oxidized to I₂.The change in the oxidation number is from -1 to 0.Hence this half-reaction is the oxidation reaction.

On the other hand, the reduction half-reaction is the gain of electrons, with the consequent reduction of the oxidation state by the reduced substance.

In this case, the process that shows the gain of electrons is:

Cl₂ + 2e⁻ → 2Cl⁻

That reaction shows:

Two Cl atoms gain two electrons (one each) to be reduced to Cl⁻.The change in the oxidation number is from 0 to - 1.Hence, this half-reaction is the reduction reaction.

Summary:

2I ⁻ → I₂ + 2e⁻ describes the oxidation.Cl₂ + 2e⁻ → 2Cl ⁻ describes the reduction.

Answer from: Quest

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is $1s^{2}2s^{2}2p^{6}3s^{1}$ and electronic configuration of phosphorous is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

$3na + p \rightarrow na_{3}p$

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

Electrons are transferred from atoms of to atoms of this transfer makes the sodium atoms and the

Answer from: Quest

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.

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Iodine, i2, has many uses, including the production of dyes, antiseptics, photographic film, pharmac...

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