You are asked to make 43 grams of iron (fe) from iron iii oxide (fe2o3) and carbon monoxide (co) as shown in the chemical equation below. fe2o3 + 3co → 2fe + 3co2 how many grams of iron iii oxide must you use? question 10 options: 61.49 g 122.99 g 0.77 g 6863 g

=61.49 g

Explanation:

From the equation, we see that 1 mole of iron (III) oxide produces 2 moles of iron.

1 mole of iron (III) oxide has a mass of: (55.845×2+ 15.995×3) = 159.675 grams

43 grams into moles = 43g/55.845g/mol= 0.77 moles

If one mole of Iron (III) oxide produces 2 moles of iron, then 0.77 moles of iron is produced by:

1×0.77 moles / 2= 0.385 moles

Thus 0.385 moles has a mass of:

0. 385 moles × 159.675 grams =  61. 5 grams