How much heat is released when 15.0 g of water vapor is condensed and then cooled from 100.0 c to -32.0 c? show work ❤️

46148 J

Explanation:

You need to calculate the heat associated with each of the following steps. You will need to know some specific heats (they are probably given to you somewhere).

Step #1: Condensation

Step #2: Cooling from 100 C to 0 C

Step #3: Freezing

Step #4: Cooling from 0 C to -32 C

Step #1:

q = mC

q = 15 g (-2256 J/g )

q = -33840 J

Step #2:

q = mcΔT

q = 15 g (4.19 J/g/C)(-100 C)

q = 6285

Step #3:

q = mC

q = 15 g (-334 J/g)

q = -5010

Step #4:

q = mcΔT

q = 15 g (2.11 J/g/C)(-32 C)

q = -1013

Keep in mind the - signs indicate heat is being released. To calculate the total heat released, add the individual heats calcualted at each step:

Total heat released = 33840 + 6285 + 5010 + 1013 = 46148 J

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

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