Aballoon is filled with a gas to a certain volume at a certain pressure at 0.987°c. if the pressure exerted on the balloon is doubled, what must the temperature (in °c) be to keep the balloon inflated at the same volume?

The temperature (in °C)  to keep the balloon inflated at the given volume is  275. °C.

Temperature is a measurement of degree that tells the coldness or hotness of any substance.

Given,

Temperature =0.987°C

converted into kelvin -0.987 + 273.15 K = 274.137 K

By Gay-Lussac's law

The pressure and temperature of the gases are in direct proportion at constant volume.

Converting kelvin to Celsius:

548.274 - 273.15 = 275.124 °C

Thus, the temperature is  275. °C.

Learn more about temperature, here:

link

Explanation:

1) Data:

a) Constant volume

b) Initial pressure: P₀

c) Intitial temperature: T₀ = 0.987°C = 0.987 + 273.15 K = 274.137 K

d) Final pressure: P₁ = 2 P₀

e) Final temperature: unknown, T₁

2) Applied principles:

        ⇒ P / T = constante ⇒ P₁ / T₁ = P₀ / T₀

3) Solution:

a) Solve for T₁

b) Substitute the data:

c) Converto to °C:

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b