Jason combines the two intermediate steps shown. na(g)+o2(g) -> 2no(g) 2no(g)+o2(g) 2no2(g) which best describes what jason should do with the oxygen molecules? place two of them as products. place two of them as reactants. cancel them out because there is one in each equation. double them because there is one in each equation.

Place two of them as reactants.

Explanation:

1) N₂(g ) + O₂(g) → 2NO(g).

2) 2NO(g )+ O₂(g) → 2NO₂(g).

N₂(g ) + 2O₂(g) → 2NO₂(g).

NO is cancelled out because there is one in each equation in the products side in eq. 1 and in oriduct side in eq. 2.

So, we place two of oxygen as reactants.

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.