Yasmin's teacher asks her to make a supersaturated saline solution. her teacher tells her that the solubility of the salt is 360 g/l at room temperature (25 °c). how can yasmin make a supersaturated saline solution? she can add 380 g of salt to 1 l of hot water (75 °c) and stir until all the salt dissolves. then, she can carefully cool the solution to room temperature (25 °c). she can add 360 g of salt to 1 l of room temperature water (25 °c) and stir the solution until all the salt dissolves. she can add 380 g of salt to 1 l of cold water (5 °c) and stir the solution until most of the salt dissolves. then, she can carefully heat the solution to room temperature (25 °c). she can add 380 g of salt to 1 l of room temperature water (25 °c) and let the solution sit for 24 hours, so the salt dissolves.

She can add 380 g of salt to 1 L of hot water (75 °C) and stir until all the salt dissolves. Then, she can carefully cool the solution to room temperature.  

Explanation:

A supersaturated solution contains more salt than it can normally hold at a given temperature.

A saturated solution at 25 °C contains 360 g of salt per litre, and water at 70 °C can hold more salt.

Yasmin can dissolve 380 g of salt in 1 L of water at 70 °C. Then she can carefully cool the solution to 25 °C, and she will have a supersaturated solution.

B and D are wrong. The most salt that will dissolve at 25 °C is 360 g. She will have a saturated solution.

C is wrong. Only 356 g of salt will dissolve at 5 °C, so that's what Yasmin will have in her solution at 25 °C. She will have a dilute solution.

in chemistry, a solution’s concentration is how much of a dissolvable substance, known as a solute, is mixed with another substance, called the solvent. the standard formula is c = m/v, where c is the concentration, m is the mass of the solute dissolved, and v is the total volume

the ratio of the conjugate base to the acid required to attain the desired ph.