Two metal blocks that have slightly different temperatures are placed next to one another. after five minutes, they both have lower but equal temperatures. according to the law of conservation of energy, what  most likelyhappened? energy was created inside the blocks. energy was destroyed inside the blocks. energy was absorbed into the blocks from outside the system. energy was transferred from the warmer block to the cooler block.

Energy was transferred from the warmer block to the cooler block

Explanation:

None of the above.

Explanation:

If the blocks were an isolated system, the cooler block would warm up.

However, both blocks cooled down, so they both must have transferred heat energy to their surroundings.

A and B are wrong. According to the Law of Conservation of Energy, energy can neither be destroyed nor created.

C is wrong. If energy was absorbed into the blocks from outside the system, the cooler block would have warmed up.

D is partially correct. Both blocks must be hotter than their surroundings. If the cooler block gets colder, it must have transferred heat energy to the surroundings. The warmer block also lost energy to the surroundings. However, it could have transferred some energy to the cooler block, which then lost it to the surroundings. The final temperature of each block is the temperature of the surroundings.

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

if you're asking what comes out, it's steam.