The molarity of hydroiodic acid in the titration is 0.485 M.
To calculate the molarity of acid, we use the equation given by neutralization reaction:
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is
We are given:
Putting values in above equation, we get:
Hence, the molarity of hydroiodic acid is 0.485M.
i'm assuming that the correct answer is indeed the first one/ "a"..
o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante