The molarity of a vinegar solution is 0.90m. calculate the nimber of acetic acis moles is 10 ml of the solution

0.009 mol.

Explanation:

M = (no. of moles of acetic acid)/(Volume of the solution (L)).

M = 0.9 M, Volume of the solution = 10.0 mL = 0.01 L.

∴ no. of moles of acetic acid = (M)(Volume of the solution (L)) = (0.9 M)(0.01 L) = 0.009 mol.

thats a little if u want the answer just look it up on google thats what i do haha : )

i would say b

explanation:

but i think i would need more information than that