Acompound is 54.53% c,54.53% c, 9.15% h,9.15% h, and 36.32% o36.32% o by mass. what is its empirical formula? insert subscripts as needed. empirical formula: chocho the molecular mass of the compound is 132 amu.132 amu. what is its molecular formula? insert subscripts as needed. molecular formula: cho

Answer : The molecular of the compound is,

Solution : Given,

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 54.53 g

Mass of H = 9.15 g

Mass of O = 36.32 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of C =

Moles of H =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For H =

For O =

The ratio of C : H : O = 4 : 8 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula =

The empirical formula weight = 12(4) + 8(1) + 1(16) = 72 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

Molecular formula =

Therefore, the molecular of the compound is,

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