A25.0 ml sample of an acetic acid solution is titrated with a 0.175 m naoh solution. the equivalence point is reached when 26.6 ml of the base is added. the concentration of acetic acid in the sample was m.

.186 M

Explanation:

Remember, the equivalence point is reached when the number of moles of the two reactants is the same.

1. For this problem, obtain the number of moles of NaOH by multiplying the concentration and volume given.

2. Once obtain, the number of moles must be the same for the weak acid.

3. With step two in mind, simply solve for molarity by dividing the value obtained and 25 mL.

Calculation.

1. moles of NaOH = (.175)(.0266) = 4.66e-3

2. moles of Acetic acid = 4.66e-3

3. Concentration of acetic acid: (4.66e-3)/(.025) = .186 M

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).