The balanced equation for the reaction of aqueous pb(clo3)2 with aqueous nai is pb(clo3)2(aq)+2nai(aq)⟶pbi2(s)+2nac lo3(aq) what mass of precipitate will form if 1.50 l of concentrated pb(clo3)2 is mixed with 0.200 l of 0.210 m nai? assume the reaction goes to completion. mass of precipitate:

Answer : The mass of precipitate produced will be, 9.681 grams.

Explanation : Given,

Molarity of NaI = 0.210 M

Volume of solution = 0.2 L

Molar mass of = 461.01 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of .

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react to give 1 mole of

So, 0.042 moles of react to give moles of

Now we have to calculate the mass of .

Therefore, the mass of precipitate produced will be, 9.681 grams.

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

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