What is the formula equation for the reaction between sulfuric acid and dissolved sodium hydroxide if all products and
reactants are in the aqueous or liquid phase?
hcl(aq) + naoh(aq) → nacl(s) + h20(1)
h2so4(aq) + ca(oh)2(aq) → caso4(aq) + 2h20(1)
h2so4(aq) + 2naoh(aq) → na2so4(aq) + 2h2o(1)
2h3po4(aq) + 3ca(oh)2(aq) → ca3(po4)(s) + 6h2o(1)

H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O(1)

Explanation:

C,   H₂SO₄(aq) + NaOH(aq)   → Na₂SO₄(aq) +  H₂O(I)

Explanation:

edge

1 a

2 d

3 a

4 c

explanation:

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.