Magnesium and nitrogen react in a combination reaction to produce magnesium nitride: 3 mg + n2→ mg3n2 in a particular experiment, a 5.65-g sample of n2 reacts completely. the mass of mg consumed is g.

The mass of magnesium consumed will be 14.731 g.

Explanation:

To calculate the number of moles, we use the equation:

 .....(1)

Given mass of nitrogen gas = 5.65 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in above equation, we get:

For the given chemical equation:

By Stoichiometry of the reaction:

1 mole of nitrogen gas reacts with 3 moles of magnesium.

So, 0.202 moles of nitrogen gas will react with = of magnesium.

Now, calculating the mass of magnesium by using equation 1, we get:

Moles of magnesium = 0.606 moles

Molar mass of magnesium = 24.31 g/mol

Putting values in equation 1, we get:

Hence, the mass of magnesium consumed will be 14.731 g.

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