Given the following equation: > 8 co2 10 h20 2 с4н10 + 13 02 how many grams of c4h10 are needed to react with 35.1 grams of o2?

The mass of butane reacting with oxygen gas is 9.76 grams.

Explanation:

To calculate the number of moles, we use the equation:

   .....(1)

Given mass of oxygen gas = 35.1 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

For the given chemical reaction:

By stoichiometry of the reaction:

13 moles of oxygen gas is reacting with 2 moles of butane.

So, 1.096 moles of oxygen gas will react with = of butane.

Now, calculating the mass of butane from equation 1, we get:

Molar mass of butane = 58.12 g/mol

Moles of butane = 0.168 moles

Putting values in equation 1, we get:

Hence, the mass of butane reacting with oxygen gas is 9.76 grams.

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first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j