What is the total reduction potential of a cell in which lithium (li) is reduced and mercury (hg) is oxidized?

The total reduction potential of the cell is -3.89 V.

Explanation:

We are given:

Reduction of lithium follows the reaction:

The standard reduction potential for this is -3.04 V

Oxidation of mercury follows the reaction:

The standard reduction potential for this is -0.85 V

The cell formed by these half reactions is:

The cell potential,

Hence, the total reduction potential of the cell is -3.89 V.

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.

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