Consider the titration of 100.0 ml of 0.200 m ch3nh2 by 0.100 m hcl. for each volume of hcl added, decide which of the components is a major species after the hcl has reacted completely. kb for ch3nh2 = 4.4 x 10-4. 0.00 ml hcl added 50.00 ml hcl added

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

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