The combustion of titanium with oxygen produces titanium dioxide:
ti (s) + o2 (g) → tio2 (s)
when 2.060 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 °c to 91.60 °c. in a separate experiment, the heat capacity of the calorimeter is measured to be 9.84 kj/k. the heat of reaction for the combustion of a mole of ti in this calorimeter is kj/mol.
ti = 47.867 amu
o2 = 31.9988 amu
tio2 = 79.8650 amu
report answer in scientific notation use en rather than x 10n

The heat of reaction for the combustion of a mole of Ti in this calorimeter is .

Explanation:

Moles of titanium =

Heat absorbed by the bomb caloriometer on combustion of 0.04303 mol of titanium be Q

The heat capacity of the bomb caloriometer  =c = 9.84 kJ/K

Change in temperature of the bomb caloriometer :

=ΔT=91.60 °C-25.00 °C=66.6 °C = 339.75 K

Q = c × ΔT

3,343.14 kJ of heat energy was released when 0.04303 moles of titanium undergone combustion.

So for 1 mol of titanium:

The heat of reaction for the combustion of a mole of Ti in this calorimeter is .

um i think it might be a car?