You have 3.00 l of a 3.00 m solution of nacl(aq) called solution a. you also have 2.00 l of a 2.00 m solution of agno3(aq) called solution b. you mix these solutions together, making solution c. hint: agcl is a precipitate. calculate the concentrations (in m) of the following ions in solution c. no3-

The concentration of nitrate ions in solution is 0.8 M.

Explanation:

In solution A;

Moles of sodium chloride in solution:

Moles of sodium chloride = 9 mole

In solution B;

Moles of sodium chloride in solution:

Moles of sodium chloride = 4 mole

In solution C;

1 mol of silver chloride reacts with 1 mol of sodium chloride to give 1 mol of silver chloride and 1 mol of sodium nitrate.

Then 4 mol silver chloride reacts with 4 mol of sodium chloride to give 4 mol of silver chloride and 4 mol of sodium nitrate.

1 mol silver nitrate gives 1 mol of nitrate ions.

So, 4 moles of silver nitrate will gives 4 mole of nitrate.

Total volume of solution = 3.00 L+ 2.00 L = 5.00 L

Concentration of nitrate ions in solution:

The concentration of nitrate ions in solution is 0.8 M.