If the pressure at a depth of 8 ft below the surface of a stagnant fluid is 3.5 psi, what will the pressure of the liquid be at a depth of 48 ft below the surface?

Answer : The pressure of the liquid at depth of 48 ft below the surface of fluid is, 21 psi.

Explanation : Given,

The pressure of the liquid at depth 8 ft = 3.5 psi

Now we have to calculate the pressure of the liquid at depth 28 ft.

According to the question,

As, the depth of 8 ft below the surface of a stagnant fluid has pressure = 3.5 psi

So, the depth of 48 ft below the surface of a stagnant fluid has pressure =

Therefore, the pressure of the liquid at depth of 48 ft below the surface of fluid is, 21 psi.

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