Chemistry, 04.02.2020 16:52 kadenreynolds5

A250-ml aqueous solution contains 1.56 mc025-1.jpg 10–5 g of methanol and has a density of 1.03 g/ml. what is the concentration in ppm?
a 6.1 x 10^-8 ppm
b 1.5 x 1-^-5 ppm
c 0.061 ppm
d 15 ppm

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The right answer for the question that is being asked and shown above is that: "B 1.5 X 1-^-5 ppm." A 250-mL aqueous solution contains 1.56 mc025-1.jpg 10–5 g of methanol and has a density of 1.03 g/mL. The concentration in ppm is that 1.5 X 1-^-5 ppm

Answer from: afrox

The correct option is C.

Explanation: ppm is used to measure the concentration of solute in a given volume of solution. ppm is basically parts per million.

Mathematically,

$ppm=\frac{\text{Mass of solute (in mg)}}{\text{Volume of solution (in L)}}$

We are given:

Mass of methanol = $1.56\times 10^{-5}g=1.56\times 10^{-2}mg$ (Conversion Factor : 1g = 1000mg)

Volume of solution = 250 mL = 0.250L (Conversion Factor : 1L = 1000mL)

Putting values in above equation, we get:

$ppm=\frac{1.56\times 10^{-2}mg}{0.250L}$

Concentration of methanol = 0.062ppm

Hence, the correct option is C.

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

They can measure the amount of energy gained or lost

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A250-ml aqueous solution contains 1.56 mc025-1.jpg 10–5 g of methanol and has a density of 1.03 g/ml...